statement proposition
Polynomials of degree two or three are irreducible iff they have no roots
Statement
Let be a field and let with or . Then is irreducible over if and only if has no root in .
Remarks
The proof: if with , then , so one factor has degree . A factor of degree gives the root . The factor theorem gives the converse. For example, has no root in , so it is irreducible over . The statement fails in degree : has no real root, but it is not irreducible over .
Explanations
L1 human
A factorisation of a polynomial of degree or must have a factor of degree . A factor of degree is the same as a root. So to test irreducibility in low degree, you only look for roots.
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What this needs
To read this node, read these 19 nodes in this order. The foundations come first, and the list ends with this node.
- no evidence level
- Group concept
- Ring definition
- Commutative ring definition
- Polynomial ring definition
- Unit of a ring definition
- Zero divisor definition
- Degree of a polynomial definition
- Polynomial evaluation definition
- Integral domain definition
- Leading coefficient definition
- Root of a polynomial definition
- Irreducible element definition
- Monic polynomial definition
- Degree of a product statement
- Irreducible polynomial definition
- Division algorithm for polynomials statement
- Remainder theorem statement
- Factor theorem statement
- Polynomials of degree two or three are irreducible iff they have no roots statement
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- Impossibility of trisecting the angle 0EWXPZCSZ0
Sources
- Web https://en.wikipedia.org/wiki/Irreducible_polynomial, Simple examples
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- Impossibility of trisecting the angle 0EWXPZCSZ0