statement theorem
An algebraic extension of an algebraic extension is algebraic
Statement
Let be fields. If and are algebraic, then is algebraic.
Remarks
The proof: let have minimal polynomial over . The field is finite over , and is finite over . By the tower law, is finite, so is algebraic over . Also, if is algebraic, then and are algebraic.
Explanations
L1 human
Algebraic extensions can be stacked. If each step adds only algebraic elements, then the whole tower adds only algebraic elements.
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What this needs
To read this node, read these 19 nodes in this order. The foundations come first, and the list ends with this node.
- no evidence level
- Group concept
- Ring definition
- Commutative ring definition
- Polynomial ring definition
- Subring definition
- Unit of a ring definition
- Polynomial evaluation definition
- Field definition
- Root of a polynomial definition
- Subfield definition
- Field extension definition
- Degree of a field extension definition
- Algebraic element definition
- Intermediate field definition
- Finite extension definition
- Algebraic extension definition
- Tower law statement
- Finite extensions are algebraic statement
- An algebraic extension of an algebraic extension is algebraic statement
What depends on this
1 node uses this node, directly or through other nodes.
- Existence of an algebraic closure 0ETGBAK2CC
Sources
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Used by
- Existence of an algebraic closure 0ETGBAK2CC