statement proposition
Finite extensions are algebraic
Statement
Let be a finite extension. Then is algebraic.
Remarks
The proof: let and . The elements are linearly dependent over . A linear dependence gives a nonzero polynomial with root . So every element of has degree at most over . The converse is false, as the algebraic numbers show. An extension generated by finitely many algebraic elements is finite, by the tower law.
Explanations
L1 human
In a finite-dimensional extension, the powers of an element cannot all be independent. A dependence between the powers is a polynomial equation for the element.
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What this needs
To read this node, read these 16 nodes in this order. The foundations come first, and the list ends with this node.
- no evidence level
- Group concept
- Ring definition
- Commutative ring definition
- Polynomial ring definition
- Subring definition
- Unit of a ring definition
- Polynomial evaluation definition
- Field definition
- Root of a polynomial definition
- Subfield definition
- Field extension definition
- Degree of a field extension definition
- Algebraic element definition
- Finite extension definition
- Algebraic extension definition
- Finite extensions are algebraic statement
What depends on this
3 nodes use this node, directly or through other nodes.
- Existence of an algebraic closure 0ETGBAK2CC
- The algebraic numbers form a field 0QFTETCHKB
- An algebraic extension of an algebraic extension is algebraic 0TPWS0K1BC
Sources
- Web https://en.wikipedia.org/wiki/Algebraic_extension, Some properties