Math 2.0

statement theorem

Continuity of the inverse of a strictly monotone continuous function

Statement

Let II be an interval and let f ⁣:I→Rf \colon I \to \mathbb{R} be continuous and strictly increasing. Then J=f(I)J = f(I) is an interval, and the inverse function f−1 ⁣:J→If^{-1} \colon J \to I is continuous and strictly increasing.

Remarks

The set JJ is an interval by the intermediate value theorem. The inverse is strictly increasing and its image is the interval II. A monotone function whose image is an interval has no jumps, so f−1f^{-1} is continuous. The same holds for strictly decreasing functions. This gives the continuity of nn-th roots, of the logarithm, and of the inverse trigonometric functions.

Explanations

L1 human

The graph of f−1f^{-1} is the graph of ff reflected in the line y=xy = x. A rising unbroken graph stays rising and unbroken after the reflection.

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  1. Limit point of a set definition
  2. Sequence definition
  3. Strictly monotone function definition
  4. Limit of a function definition
  5. Real sequence definition
  6. Continuity at a point definition
  7. One-sided limit definition
  8. Bounded sequence definition
  9. Limit of a sequence definition
  10. Monotone sequence definition
  11. Continuous function definition
  12. Monotone convergence theorem for sequences statement
  13. Intermediate value theorem statement
  14. One-sided limits of a monotone function exist statement
  15. Continuity of the inverse of a strictly monotone continuous function statement

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Sources

  1. Web https://en.wikipedia.org/wiki/Inverse_function, Standard inverse functions