Math 2.0

Field theory and polynomials Proof

Proof that i squared is minus one

Builds on Imaginary unitComplex numbers

Proof

  1. The imaginary unit is the complex number i=0+1ii = 0 + 1 i, with real part 00 and imaginary part 11.
  2. The product of complex numbers is (a+bi)(c+di)=(ac−bd)+(ad+bc)i(a + b i)(c + d i) = (a c - b d) + (a d + b c) i.
  3. Take a=c=0a = c = 0 and b=d=1b = d = 1. Then i2=(0⋅0−1⋅1)+(0⋅1+1⋅0)i=−1+0ii^2 = (0 \cdot 0 - 1 \cdot 1) + (0 \cdot 1 + 1 \cdot 0) i = -1 + 0 i.
  4. The complex number −1+0i-1 + 0 i is the real number −1-1, since ℝ\R sits in ℂ\C as the numbers a+0ia + 0 i. So i2=−1i^2 = -1.

Idea

The rule for multiplying complex numbers is built so that the two imaginary parts multiply to a negative real number. For i⋅ii \cdot i this gives exactly −1-1.

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  1. Complex numbers object
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Where this leads

159 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Imaginary_unit, Definition
About this page
TagEVARG9RYTF
URIm2://EVARG9RYTF
Kindproof
WritingW0 stub
MSC12D99
Provesi squared is minus one
UsesImaginary unit, Complex numbers
Changed4 November 2026

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