Math 2.0

Commutative algebra Proof

Proof of cancellation in an integral domain

Builds on Integral domainCommutative ringRing

Proof

  1. Let RR be an integral domain, and let a,b,c∈Ra, b, c \in R with a≠0a \neq 0 and ab=aca b = a c.
  2. Subtract aca c from both sides. This gives ab−ac=0a b - a c = 0.
  3. By the distributive law of the ring RR, a(b−c)+ac=a(b−c+c)=aba (b - c) + a c = a (b - c + c) = a b. So a(b−c)=ab−ac=0a (b - c) = a b - a c = 0.
  4. In an integral domain, a product is 00 only if one factor is 00. Since a≠0a \neq 0, we get b−c=0b - c = 0.
  5. Adding cc to both sides gives b=cb = c.

Idea

Move everything to one side and factor out aa. The product a(b−c)a (b - c) is zero, and an integral domain has no zero divisors. So the factor b−cb - c must vanish, even though aa need not have an inverse.

Reading path

To understand this page from the ground up, read these 6 pages in order. The foundations come first.

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  1. Group concept
  2. Ring definition
  3. Commutative ring definition
  4. Zero divisor definition
  5. Integral domain definition
  6. Proof of cancellation in an integral domain proof

Where this leads

179 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Integral_domain, Properties
About this page
Tag2SQBC82310
URIm2://2SQBC82310
Kindproof
WritingW0 stub
MSC13G05
ProvesCancellation in an integral domain
UsesIntegral domain, Commutative ring, Ring
Changed4 November 2026

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