Math 2.0

Combinatorics Proof

Proof of Pascal's rule from the recursive definition

Builds on Binomial coefficient

Proof

  1. Let nn and kk be natural numbers.
  2. The binomial coefficient is defined by the recursion (n0)=1\binom{n}{0} = 1, (0k+1)=0\binom{0}{k+1} = 0 and (n+1k+1)=(nk)+(nk+1)\binom{n+1}{k+1} = \binom{n}{k} + \binom{n}{k+1}.
  3. The third clause of this definition, applied to nn and kk, is the equation (n+1k+1)=(nk)+(nk+1)\binom{n+1}{k+1} = \binom{n}{k} + \binom{n}{k+1}.

Idea

In this wiki the binomial coefficients are defined by Pascal's rule itself, so the rule holds by definition. With other definitions, such as the factorial formula or the count of subsets, it needs a short computation or a counting argument.

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  1. Binomial coefficient definition
  2. Proof of Pascal's rule from the recursive definition proof

Where this leads

597 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Pascal's_rule, lead section
About this page
TagEDF0ZJF141
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Kindproof
WritingW0 stub
MSC05A10
ProvesPascal's rule
UsesBinomial coefficient
Changed4 November 2026

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